-16t^2+14t+36=36

Solution for -16t^2+14t+36=36 equation:

-16t^2+14t+36=36

We move all terms to the left:

-16t^2+14t+36-(36)=0

We add all the numbers together, and all the variables

-16t^2+14t=0

a = -16; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-16)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-16}=\frac{-28}{-32}
=7/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-16}=\frac{0}{-32}
=0
$